Pandas DataFrame DataFrame.median() function
Python Pandas DataFrame.median() function calculates the median of the elements of the DataFrame object along the specified axis.
The median is not the average, but the middle value of a list of numbers.
pandas.DataFrame.median()grammar
DataFrame.median(axis=None, skipna=None, level=None, numeric_only=None, **kwargs)
parameter
axis |
Find the median along a row ( axis=0) or column ( )axis=1 |
skipna |
Boolean. Exclude NaNvalue( skipna=True) or include NaNvalue( skipna=False) |
level |
If axis is MultiIndex, then find the median along a specific level |
numeric_only |
Boolean. Boolean. For numeric_only=True, only include float, int, and booleancolumns |
**kwargs |
Additional keyword arguments to functions |
Return Value
If not specified level, returns the median along the requested axis Series, otherwise returns the median DataFrame.
Example Code: DataFrame.median()Method to find the median along the column axis
import pandas as pd
df = pd.DataFrame({'X': [1, 2, 7, 5, 10],
'Y': [4, 3, 8, 2, 9]})
print("DataFrame:")
print(df)
medians=df.median()
print("medians of Each Column:")
print(medians)
Output:
DataFrame:
X Y
0 1 4
1 2 3
2 7 8
3 5 2
4 10 9
medians of Each Column:
X 5.0
Y 4.0
dtype: float64
Computes the median of two columns, Xand Y, and returns a object containing the median of each column Series.
In Pandas, to find the median of a column in a DataFrame, we just call median()the median function on that column.
import pandas as pd
df = pd.DataFrame({'X': [1, 2, 7, 5, 10],
'Y': [4, 3, 8, 2, 9]})
print("DataFrame:")
print(df)
medians=df["X"].median()
print("medians of Each Column:")
print(medians)
Output:
DataFrame:
X Y
0 1 4
1 2 3
2 7 8
3 5 2
4 10 9
medians of Each Column:
5.0
It just gives the median of the columns DataFramein .X
Example Code: DataFrame.median()Method to find the median along the row axis
import pandas as pd
df = pd.DataFrame({'X': [1, 2, 7, 5, 10],
'Y': [4, 3, 8, 2, 9],
'Z': [2, 7, 6, 10, 5]})
print("DataFrame:")
print(df)
medians=df.median(axis=1)
print("medians of Each Row:")
print(medians)
Output:
DataFrame:
X Y Z
0 1 4 2
1 2 3 7
2 7 8 6
3 5 2 10
4 10 9 5
medians of Each Row:
0 2.0
1 3.0
2 7.0
3 5.0
4 9.0
dtype: float64
It calculates the median of all rows and returns a Seriesobject containing the median for each row.
In Pandas, to find DataFramethe median of a row in , we just call median()the function to calculate the median of that row.
import pandas as pd
df = pd.DataFrame({'X': [1, 2, 7, 5, 10],
'Y': [4, 3, 8, 2, 9],
'Z': [2, 7, 6, 10, 5]})
print("DataFrame:")
print(df)
median=df.iloc[[0]].median(axis=1)
print("median of 1st Row:")
print(median)
Output:
DataFrame:
X Y Z
0 1 4 2
1 2 3 7
2 7 8 6
3 5 2 10
4 10 9 5
median of 1st Row:
0 2.0
dtype: float64
It only gives DataFramethe median of the first row of values in .
We use ilocthe method to select a row based on its index.
Example Code: DataFrame.median()Method Ignoring NaNValues to Find the Median
We use skipnathe default value of the parameter, that is , find the median of along the specified axis skipna=Trueby ignoring the value of .NaNDataFrame
import pandas as pd
df = pd.DataFrame({'X': [1, 2, 7, None, 10, 8],
'Y': [None, 3, 8, 2, 9, 6],
'Z': [2, 7, 6, 10, None, 5]})
print("DataFrame:")
print(df)
median=df.median(skipna=True)
print("medians of Each Row:")
print(median)
Output:
DataFrame:
X Y Z
0 1.0 NaN 2.0
1 2.0 3.0 7.0
2 7.0 8.0 6.0
3 NaN 2.0 10.0
4 10.0 9.0 NaN
5 8.0 6.0 5.0
medians of Each Row:
X 7.0
Y 6.0
Z 6.0
dtype: float64
If we set skipna=True, it ignores the in DataFrame NaN. It allows us NaNto calculate DataFramethe median along the column axis by ignoring the values.
import pandas as pd
df = pd.DataFrame({'X': [1, 2, 7, None, 10],
'Y': [5, 3, 8, 2, 9],
'Z': [2, 7, 6, 10, 4]})
print("DataFrame:")
print(df)
median=df.median(skipna=False)
print("medians of Each Row:")
print(median)
Output:
DataFrame:
X Y Z
0 1.0 5 2
1 2.0 3 7
2 7.0 8 6
3 NaN 2 10
4 10.0 9 4
medians of Each Row:
X NaN
Y 5.0
Z 6.0
dtype: float64
Here, we get NaNthe value as Xthe median of the column because Xthere are values in the column NaN.
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