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Convert 3D array to 2D array in Python

Author:JIYIK Last Updated:2025/05/03 Views:

In this tutorial, we will discuss the methods to convert 3D array to 2D array in Python.


numpy.reshape()Convert 3D array to 2D array using function in Python

[ numpy.reshape()Function](numpy.reshape - NumPy v1.20 manual)Changes the shape of an array without changing its data. numpy.reshape()Returns an array with the specified dimensions. For example, if we have a (4, 2, 2)3D array of size , we want to convert it to (4, 4)a 2D array of size .

The following code example shows us how to use numpy.reshape()the function in Python to convert a 3D array of size (4, 2, 2)to (4, 4)a 2D array of size.

import numpy

arr = numpy.array(
    [[[0, 1], [2, 3]], [[4, 5], [6, 7]], [[8, 9], [10, 11]], [[12, 13], [14, 15]]]
)
newarr = arr.reshape(4, 2 * 2)
print(newarr)

Output:

[[ 0  1  2  3]
 [ 4  5  6  7]
 [ 8  9 10 11]
 [12 13 14 15]]

In the above code, we first numpy.array()initialize a 3D array using the function arrand then numpy.reshape()convert it to a 2D array using the function newarr.

The following code example demonstrates another way to perform the same operation if, for some reason, we don't know the exact dimensions of the 3D array.

import numpy

arr = numpy.array(
    [[[0, 1], [2, 3]], [[4, 5], [6, 7]], [[8, 9], [10, 11]], [[12, 13], [14, 15]]]
)
newarr = arr.reshape(arr.shape[0], (arr.shape[1] * arr.shape[2]))
print(newarr)

Output:

[[ 0  1  2  3]
 [ 4  5  6  7]
 [ 8  9 10 11]
 [12 13 14 15]]

In the code above, we numpy.shape()specify the dimensions of using the function newarr. The numpy.shape() function returns a tuple containing an element in each dimension of the array.

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