Printing a list without square brackets in Python

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Printing a list without square brackets in Python

Author：JIYIK Last Updated：2025/05/09 Views：

This tutorial shows you how to print a list without showing the square brackets.

`join()`Printing a list without square brackets in Python using the function

join()The function takes all elements from an iterable object, such as a list, and returns a string with all elements separated by the character specified by the function. Using this method, we can remove the square brackets from the list and use commas or any character we want to separate the elements. The following code snippet achieves this.

lst = ["x", "y", "z"]
print(",".join(lst))

Output:

x,y,z

Note that this method only works for lists containing strings, not for lists of integers or floating point numbers.

Printing Lists Without Square Brackets Using Unpack Method in Python

The operator in Python *can be used to unpack objects. It unpacks all the elements in a list and prints them without the square brackets, as shown below.

lst = ["x", "y", "z"]
print(*lst, sep=",")

Output:

x,y,z

We use septhe character specified in the parameter to separate the elements, and remove it if necessary.

Use `str`the function to print a list without square brackets

In this method, we use str()the function to convert a list into a string, and then remove the first and last characters of the square brackets from the string. The following code shows how to do it.

lst = [1, 2, 3]
lst_str = str(lst)[1:-1]
print(lst_str)

Output:

1, 2, 3

Note that this method also works on lists containing integers or floating point numbers.

Another way we can use this function is to convert each element of the list into a string. We can then use join()the function discussed earlier to continue removing the brackets. For example,

lst = [1, 2, 3]
lst_new = [str(a) for a in lst]
print(",".join(lst_new))

Output:

1,2,3

In the code above, we use strthe function to convert all the elements from lstto string values and create a new list using list comprehension approach lst_new.

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