Remove all occurrences of an element from a Python list
In Python, lists allow the same element to appear multiple times. Even though the value of an element may be the same as other elements, each element will have a different index. Using these index numbers, you can easily access any element you want.
However, in some cases, you may not want multiple instances of the same element; then, you would definitely want to remove all those occurrences of that particular element from the list. In Python, there are different ways to achieve this.
filter()
Use the function to remove all instances of an element from a list in Python
In Python, filter()
filtering elements becomes easier with the help of functions. filter()
Functions require two parameters, the first parameter is a function, and the second parameter can be a collection, list, tuple, etc.
Example 1: Function __ne__
withfilter()
myList = [2, 1, 3, 5, 1, 1, 1, 0]
myList = list(filter((1).__ne__, myList))
print(myList)
Output:
[2, 3, 5, 0]
In this example, you have a list myList
from which you want to remove all occurrences of 1
. filter()
The remove function takes another function __ne__
that will return a boolean value of either or , depending on 1
whether exists in the list . If the value exists in the list, then it will simply discard it. Then, whatever the remove function returns will be converted into a list using the remove function.myList
True
False
1
filter()
list()
Example 2: Function with lambda
functionfilter()
myList = [2, 1, 3, 5, 1, 1, 1, 0]
valueToBeRemoved = 1
result = filter(lambda val: val != valueToBeRemoved, myList)
print(list(result))
Output:
[2, 3, 5, 0]
__ne__
Instead of passing a function, we pass a lambda
function to filter()
the function.
From the list myList
, you will extract each element one by one and store it in val
the variable . If the elements present in val
and valueToBeRemoved
are not equal, only those val
elements present in will be added to the new variable result
. You should convert to a list using list()
the function result
.
Remove all instances of an element from a list using list comprehensions in Python
List comprehensions are a shorthand way to write code. List comprehensions are faster than regular functions and loops.
Sample code:
myList = [1, 2, 3, 4, 2, 2, 3]
valueToBeRemoved = 2
myList = [value for value in myList if value != valueToBeRemoved]
print(myList)
Output:
[1, 3, 4, 3]
You have a list myList
from which you want to remove 2
the occurrences of an element . The main code to remove all instances of an element is []
inside the square brackets . Here, for
the loop will run first and then it will myList
take a value from the list and store it value
in the variable. After that, if value
the value inside the variable and valueToBeRemoved
the variable do not match, it will simply return value
the value of the variable and store it in the list myList
. This process will continue until the list becomes empty. At the end, you will have a list with the output you wanted.
Use remove()
the function to remove all instances of an element from Python
remove()
The function removes only the first occurrence of an element. If you want to remove()
remove all occurrences of an element using the function, you can use for
a for loop or while
a for loop.
myList = [2, 1, 3, 5, 1, 1, 1, 0]
valueToBeRemoved = 1
try:
while True:
myList.remove(valueToBeRemoved)
except ValueError:
pass
print(myList)
Output:
[2, 3, 5, 0]
In the code above, you create a list myList
and then you have a variable valueToBeRemoved
that will contain the element you want to remove from the list, in this case 1
. When looping through the list, if the element is in the list, it will be remove()
removed from the list using the .
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